Creates rows of data based either on a specified number of rows, a specified generation period (in seconds), or both. 2 days. For example, TRUNC (TO_DATE ('2013-08-05'), 'QUARTER') returns the first date in the third quarter of the year 2013, which is July 1, 2013. "TargetTable" (AddressTypeID ,1 Answer. date, DATEDIFF ('day', first_action. 1. Die Funktion gibt das Ergebnis der Subtraktion des zweiten Arguments vom dritten Argument zurück. 要求された日付または時刻の部分に基づいて、2つの日付、時刻、またはタイムスタンプ式の差を計算します。この関数は、3番目の引数から2番目の引数を減算した結果を返します。 マイナス記号（-）を使用して日付を減算することもできます。Truncates a DATE, TIME, or TIMESTAMP to the specified precision. When specified as a time, then the DATEDIFF function sets the missing date part to 1900-01-01. ほとんどのユースケースでは、Snowflakeは文字列としてフォーマットされた日付とタイムスタンプの値を正しく処理します。Some databases, such as Snowflake and BigQuery, support functions like DATEDIFF or DATE_DIFF. insertedon,1,10))) There is any simple way to do this? just a subtraction of 2 hours to date time Regards The syntax for using the DATEDIFF function in Snowflake and Amazon Redshift, and Databricks looks like the following: datediff ( < date part > , < start date / time > , < end date / time > ) A note on Databricks: Databricks additionally supports a separate DATEDIFF function that takes only two arguments: a start date and an end date. I run the following task in Snowflake to see which queries are candidates for inefficiency improvements: select datediff (second,scheduled_time,query_start_time) as second, * from table (information_schema. Like Liked Unlike Reply. 1 Answer. You can only run them separately. If the clicked date and the claimed date are set to '2999-12-31' then subtract deadline_date - bought_date. For clarity, I would explicitly convert to character strings:Oct 22, 2022. In certain cases, such as string-based comparisons or when a result depends on a different timestamp format than is set in the session parameters, we recommend explicitly converting. Thanks, Rag. here is one. 1 Answer. Note, that since DATEDIFF returns an integer value, the result also will be an integer. Example:Usage Notes¶. @nehan it looks like you were able to solve your issue, that is so great! It would mean a lot if you can select the "Best answer" yourself to help others find the right answer faster. Can anybody help how can we pass dynamic dates in snowflake View/Table. Thus select DATEDIFF('year', '2020-12-31', '2021-01-01') returns 1 because there's 1 year difference between 2020 and 2021, even though there's only actually 1 day between these 2 dates. date_or_time_part 은. Fractional seconds are not rounded. DATEDIFF(YY, @DOB, @NOW) - CASE WHEN DATEADD(YY, DATEDIFF(YY, @DOB, @NOW), @DOB) > @NOW THEN 1 ELSE 0 END It's actually adding difference in years to DOB and if it is bigger than current date then subtracts one year. The following table lists all the valid datepart values. February 28 and March 28) and when the days of the month are the last day of the month (e. Cognos will convert this to DATEDIFF but the arguments are reversed in the 2 functions. Arguments¶ percentile. Supported date and time parts. The parameter group bounds changes the way the join happens in a. The DATEDIFF function will still work, but you'll want to make sure the input parameters are correct. The syntax for DATEDIFF is pretty straightforward: DATEDIFF (datepart, startdate, enddate) Let’s explore the parameters used here: datepart: The unit of time you want to use for the calculation, like year, quarter, month, day, or even smaller units like hour, minute, or second. checkin_date, '2018-08-01') <= 90, 1, 0)) as visits_past_90_days, from user_checkin as uc where uc. functions. Learn how to use the DATEDIFF function in Snowflake to calculate the difference between two date, time, or timestamp expressions based on the date or time part requested. Write resolution instructions: Use bullets, numbers and additional headings Add Screenshots to explain the resolution Add diagrams to explain complicated technical details, keep the diagrams in lucidchart or in google slide (keep it shared with entire Snowflake), and add the link of the source material in the Internal comment section Go in depth if required Add links and other resources as. The function returns the result of subtracting. I tried with this, but this is the last 7 days, without considering week end or start. Thanks @SimeonPilgrim. g. Do not use the returned value for precise time ordering between concurrent queries. DATEDIFF (WEEK,. g. It may be positive or negative. Extracts the corresponding time part from a time or timestamp value. Returns the number of days from startDate to endDate. This works fine: SELECT. I want to be able to compare the date between the first record and any future records for that card id where that future record's legit = 0, and if the first record is within 10 days, show that record. I'm having trouble getting it to run in snowflake. It assumes that two given dates are business days. – Simeon Pilgrim. I tried to define the correct start date with a SQL CASE before i start the AVG(DATEDIFF). date_or_time_part must be one of the values listed in Supported Date and Time Parts. 3 Answers. snowflake. Commonly used datepart units include month or second. The int difference between the startdate and enddate, expressed in the boundary set by datepart. The function returns the result of subtracting the second argument from the third argument. The DateDiff function returns how many seconds, months, years - whatever interval you specify between the first date (here 0) and the second date (here the current date). Timestamp Datatypes in Snowflake. As shown clearly in the result, because 2016 is the leap year, the difference in days between two dates is 2×365 + 366 = 1096. The DATEDIFF command takes a datepart and returns the difference between two dates or timestamps. SnowflakeのDATEDIFF関数では、指定している単位（今回は「DAY」）の数値のズレを計算するため、BQとは異なる結果が出力される。 そのため、例えば、5月8日の23時39分20秒と日付が変わった瞬間の時刻の差分を計算すると、実際には20分程度しかたっていないにも. date_or_time_expr (Required) must be a date or timestamp expression. 848 -0400 (now it's twelve o'clock). Modified 6 years, 9 months ago. The units are used is a Date part ( year, month, date ) or Time part (hours, minute, second). Use conditional aggregation: select id1, id2, avg (case when datediff < 14 then n_products end) as avg_lt14, avg (case when datediff >= 14 and datediff <= 28 then n_products end) as avg_14_28, avg (case when datediff > 29 then n_products end) as avg_29pl from t group by id1, id2; Some databases calculate the averages of integers as. Berechnet die Differenz zwischen zwei Datums-, Zeit- oder Zeitstempelausdrücken anhand der angeforderten Datums- oder Zeitkomponente. I am new to snowflake. If you want the difference, then use datediff () or timestampdiff (). In this article, we will check what are c ommonly used date functions in the Snowflake cloud data warehouse. Snowflake does: unit_answer = TRUNC( unit, to_date ) - TRUNC( unit, from_date);. Sorted by: 0. Snowflakeは、整数を秒として解釈することが意図されている場合にのみ、整数を含む文字列で TO_DATE、 TO_TIME または TO_TIMESTAMP を呼び出すことをお勧めします。. SELECT date1, date2 FROM (VALUES ('2020-01-02'::date, '2020-04-01'::date), ('2020-02-01'::date, '2020-03-09'::date), ('2021-01-04'::date, '2021-04-09'::date) v (date1, date2) ) WHERE abs (datediff ('days', date1, date2)) > 45 ; Now I used ABS. User Conference. If you need the difference in seconds (i. 1. For DATEDIFF: date_or_time_expr1 and date_or_time_expr2 can be a date, time, or timestamp. Follow asked Feb 4, 2022 at 0:30. Invalid function type [DATEDIFF] for window function. select t. Grants_To_Users. I want to find the time difference between two timestamps for each id . datediff(part: str, col1: Union[Column, str], col2: Union[Column, str]) → Column[source] Calculates the difference between two date, time, or timestamp columns based on the date or time part requested, and returns result of col2 - col1 based on the requested date or time part. Account_Usage. snowflake. A general expression. The function returns the result of subtracting the second argument from the third argument. tbl_1 where month (datecompleted) = month (dateadd (month,-1,current_timestamp)) and year (datecompleted) = year (dateadd (month,-1,current_timestamp)) and ApprovalRequiredFrom = 'GRM' and DATEDIFF (DAY, xx, yy). 2021-06-10 12:07:04. DATEDIFF(MONTH, 0, '2-14-2015') --returns month. You should add another column to indicate the type of count you're calculating, but you can accomplish this with datediff,last_day, and date_trunc(to get first of month). datediff (part: str, col1: Union [Column, str], col2: Union [Column, str]) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested, and returns result of col2 - col1 based on the requested date or time part. This makes that answer appear right after the question so it's easier to find within a thread. Date). List months between two dates in snowflake table. Snowflake. 1239') は1. Consulte também: TIMEDIFF, TIMESTAMPDIFFCurrently, my code just returns zero on the right side of the decimal place. TIMEADD: Adds the specified value for the specified date. Invalid function type [TIMEDIFF] for window function. Usage Notes¶. Write resolution instructions: Use bullets, numbers and additional headings Add Screenshots to explain the resolution Add diagrams to explain complicated technical details, keep the diagrams in lucidchart or in google slide (keep it shared with entire Snowflake), and add the link of the source material in the Internal comment section Go. Window functions operate on windows, which are groups of rows that are related (e. Arguments¶ source_expr. Then you can run a fairly simple query: select t. datediff. When calculating it, only from 9am till 17pm and weekdays are needed to be accounted. DATEDIFF — Snowflake Documentation; PIVOT — Snowflake Documentation; I cannot seem to get pivot to work in SQL Snowflake (conditional aggregation), Stack Overflow; Pivot Tables. Datediff didn't work: DATEDIFF(hour,2,TO_DATE(substr(p. Learn more about Teamssnowflake. Let’s look at the clear differences between the two. October 10, 2023. BOO_DateCI, ___Bookings. In Snowflake, if any part of the concatenation is null, the entire result is null. snowflake. DATEDIFF (date_part, date1, date2) Where, date_part parameter is the part of the date like day, month, and year, which you want to use in your computation. g. Learn how to use the datediff function in Snowflake SQL to calculate the difference between two dates or times. For seconds: DATEDIFF (second, LAG (ACTION_DATE) OVER (PARTITION BY users ORDER BY ACTION_DATE), ACTION_DATE ) AS DIFF_SECONDS. Snowflake Date Functions. What is SUBSTRING () Function in Snowflake? SUBSTRING () function helps to get the substring from a string by providing the starting index and length of the substring. The datepart passed to DATEDIFF will control the resolution of the output. (varchar(10),(DATEDIFF(s,A. Image file Snowflake Datediff ignores timezones. * from (select t. : pip install data-diff 'data-diff [postgresql,snowflake]' -U. Tony Williams Tony Williams. Usage Notes¶. Snowflake does not allow to run session variable statement and dashboard query statement together. If you combing using BEGIN and END block then you cannot set a session variable inside the block. 0. Result: '1. The percentile of the value that you want to find. Please try a simpler expression. sql. 27' which means 270ms rather than 27ms. Note that unit values can be different in SQL Server DATEDIFF and MariaDB TIMESTAMPDIFF. approx_percentile_combine. 要求された日付または時刻の部分に基づいて、2つの日付、時刻、またはタイムスタンプ式の差を計算します。この関数は、3番目の引数から2番目の引数を減算した結果を返します。 マイナス記号（-）を使用して日付を減算することもできます。 TIMESTAMPDIFF. If only a time value is assigned to a date data type variable, DATEDIFF sets the value of the missing date part to the default value: 1900-01-01. Snowflake SQL Query - Invalid Argument Function Using DATEADD() Hot Network QuestionsSYSDATE¶. snowflake. Setting a clustering key is important on large fact tables. 2. DATEDIFF. Das Minuszeichen ( -) kann auch zum Subtrahieren von Datumsangaben. SQL Server : -- Get difference in days SELECT DATEDIFF ( dd, '2022-09-01', '2022-09-05'); # 4. datediff (part: str, col1: Union [Column, str], col2: Union [Column, str]) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. Alternative for DATEDIFF. 0. I am new to sql language and recently snowflake. 3,330 3 3. Thus select DATEDIFF('year', '2020-12-31', '2021-01-01') returns 1 because there's 1 year difference between 2020 and 2021, even though there's only actually 1 day between these 2 dates. datediff(part: str, col1: ColumnOrName, col2: ColumnOrName) → Column [source] Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. In addition, it uses object or file storage from AWS S3, Azure Blob Storage, or Google Cloud Storage for persistent storage of data. Snowflake DATEDIFF function returns the difference between 2 dates thus it doesn't accept NUMBER as an argument in place of a date. A window function is generally passed two parameters: A row. Hi @SQL Baby , Last Day of previous month：. See also:DATEDIFF. Thanks for help . Expand Post. Supported date and time parts. Below is SQL Server:Get the Average of a Datediff function using a partition by in Snowflake. SELECT DATEADD (MONTH, DATEDIFF (MONTH, -1, GETDATE ())-1, -1) Best Regards, Joy. DATEDIFF on several events for specific value - Part 2. date, returning_action. to round -0. For instance, you can sub. date_from, evnt. This unit of measure must be one of the values listed in . 함수 참조. Default is 1. I need to compare 2 dates and return the number of days in between with 2 decimal places. 0. This is how I was able to generate a series of dates in Snowflake. Sorted by: 3. This case means that if we start at startdate '2036-03-01', and then count -2 days, we reach the enddate of '2036-02-28'. snowpark. I am trying to get the same output in Snowflake, but cant figure out how to return a float. How can get a list of all the dates between two dates (current_date and another date 365 days out). functions. Solutions Engineer. So this is really two parts, to know what year-quarter something is with respect to an offset, you just need to subtract the offset month, from the date you have and then year and quarter the adjusted date. select datediff ( day, Date ('Tue Jan 01 1980 00:00:00 GMT-0800 (Pacific Standard Time)')::timestamp, Date ('Tue Jan 01 2020 00:00:00 GMT-0800 (Pacific Standard Time)')::timestamp ); The function you mentioned will return the difference in days between the two dates specified. Get the field type for each column in a table. An image can help us visualize the concept you have, but the code is what you're trying to fix. -2. was asking for, but useful for those looking to generate a list of dates in Snowflake SQL. 000. functions. Usage Notes. For example, SELECT DATEDIFF (day, '2036-03-01', '2036-02-28'); returns -2, hinting that 2036 must be a leap year. La fonction renvoie le résultat de la soustraction du deuxième argument et du troisième argument. AMA WITH MIKE TAVEIRNE Exciting news! Data Superhero, Mike Taveirne, is in forums from Sept 26-29 to answer your questions. If you are trying to use add_months rather than dateadd than the query should be . snowflake. MSSQL on the other hand does an implicit cast of '0' to DATE '1900-01-01' and returns the result in the requested date part. Syntax For DATEDIFF DATEDIFF( <date_or_time_part>, <date_or_time_expr1>, <date_or_time_expr2> ) For minus sign <date_expr2> - <date_expr1> Arguments For DATEDIFF: date_or_time_part The unit of time. The data type to which to convert the expression. There are also consideration of different rules for different countries governing how Daylight Savings Time are calculated, and sometimes the rule changes too. 有効な文字列を日付、時刻、またはタイムスタンプへの変換¶. I guess first I need to find "min_data" for value, then "next_date" and calculate "DATEDIFF". snowflake-cloud-data-platform; Share. You can even find the number of hours, minutes, seconds, and so on in terms of details in between the two. INFORMATION_SCHEMA. , DATEDIFF and DATEADD). date_or_time_part 은. Calculates the difference between two date, time, or timestamp expressions based on the specified date or time part. Usage Notes¶. datediff(part: str, col1: Union[Column, str], col2: Union[Column, str]) → Column[source] Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. Why DATEDIFF() function in Snowflake works differently while getting date difference in weeks. select post_visid_high || ':' || post_visid_low as visitor_id , lag (date_time) over (partition by visitor_id order by date_time asc) as previous_date , datediff (minute, previous_date, date_time) as difference_in_minutes from adobe_data. Learn how to use the DATEDIFF () function to calculate the difference between dates, times, or timestamps in Snowflake. Actually, the marked answer originally produced wrong results for milliseconds 1 - 99: Example 1 second, 27 milliseconds: DATEDIFF % 1000 will return 27. insertedon,1,10))) There is any simple way to do this? just a subtraction of 2 hours to date time Regards. In the first form of CASE, each condition is an expression that should evaluate to a BOOLEAN value (True, False, or NULL). convert(varchar,cast((End_Datetime-Start_Datetime) as time),108) how to convert this to snowflake snowflake. should work fine. snowpark. *, min (date) over (partition by cardid) as min_date from t ) t where legit = 0 and date < min_date + interval '10 day. Example. Invalid function type [TIMEDIFF] for window function. Need to break down a date field "DAY" to monthly and weekly wise in snowflake. functions. Consulte também: TIMEDIFF, TIMESTAMPDIFFdatediff¶. My stored procedure is static, meaning, I address the table X directly and I want it be a parameter that will be provided to stored procedureUnfortunately, at this moment Snowflake does not allow expressions in ADD COLUMN statements (only constant values) and does not allow adding a default value. select count(*) from orders. To comply with ANSI standards, this function can be called without parentheses. Date_Time, Stack Overflow. Oracle Database using Sql developer. Here is a brief and simplified extract of my current dataset: All my users currently have a start time and end time for various actions they complete. 999) from pqrquet file to snowflake. When date_or_time_part is week (or any of its variations), the output is controlled by the WEEK_START session parameter. HOUR / MINUTE / SECOND¶. Like. sql; snowflake-cloud-data-platform;. 1. date_from, evnt. A função retorna o resultado da subtração do segundo argumento do terceiro argumento. Expression to be converted into a time: For string_expr, the result of converting the string to a time. nanosecond は、時、分、秒、および小数秒の9桁すべてを使用します. For example, if we want to get the name ‘John’ from the name ‘John Rose’, then we can make use of this function as: substring (‘John Rose’,0,4). A função retorna o resultado da subtração do segundo argumento do terceiro argumento. By summarizing these two points, I have implemented the logic below. Account_Usage. I'm trying to run the following query in Snowflake but it fails with `Unsupported subquery type cannot be evaluated`. SELECT DATEDIFF (DAY, xx, yy) AS Avg_DayDiff FROM Database1. Compared to true difference in values, and then that being expressed in a time unit. set @BegDate = DATEADD(month, DATEDIFF(month, 0, getdate()) - 12, 0) -- How far back to look (-12 = 12 Months)PowerBI + Snowflake: ODBC Connection: DirectQuery. 0. For ' integer ' (a string containing an integer), the integer is treated as a number of seconds, milliseconds, microseconds, or. As Lukasz points out the second parameter is the start_month SAP doc's. Join us at Snowflake Summit 2024 to explore all the cutting-edge innovation the Data Cloud has to offer. For both DATEDIFF and minus sign: Output values can be negative, for example, -12 days. 170 Followers. In almost all cases, at least one of those expressions references a column in that row. snowpark. datediff(part: str, col1: Union[Column, str], col2: Union[Column, str]) → Column[source] Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. dow_string. I've tried the Snowflake help guide but I want to avoid executing multiple queries. datediff(part: str, col1: Union[Column, str], col2: Union[Column, str]) → Column[source] Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. DATEDIFF¶ Calculates the difference between two date, time, or timestamp expressions based on the date or time part requested. There are 3 different timestamp types in Snowflake: TIMESTAMP_NTZ. Thanks! Expand Post. The ORDER BY and LIMIT / FETCH clauses are applied to the result of the set operator. From the inputs you got there are 123 months between the date of 07/03/2011 to 24/3/2021. Push out all due dates by one week. Snowflake SQL compilation error: cannot change column from type TIMESTAMP_LTZ(9) to TIMESTAMP_NTZ(9) 2 DateTime in Snowflake Timestamp '23-Jan-2015 23:02:39' is not recognizedMin/Max of a group. DATEADD ('week', 1, [due date]) Add 280 days to the date February 20, 2021. example, if start_date and end_date differed by 59 seconds, then DATEDIFF(MINUTE, start_date, end_date) / 60. The fact that the function returns an integer number of months both when the days of the month are the same (e. Deleted my comment to avoid confusing anyone. SELECT Customer_ID , Day_ID , DATEDIFF (DAY, LAG (Day_ID) OVER (PARTITION BY Customer_ID ORDER BY. datediff(yy,'31 Dec 2013','1 Jan 2014') returns 1. date_from) = 1. SELECT date_from ,date_to ,part ,case part when 'month' then datediff ('month', date_from, date_to) when 'day' then datediff ('day', date_from, date_to) when 'hour' then datediff ('hour', date_from, date_to). Follow edited Mar 23 at 17:46. datediff¶. select dateadd (day, '-' || seq4 (), current_date ()) as dte from table (generator (rowcount => 1095))I'm am fairly new to using these systems and I am trying to convert the below statement for Snowflake, but no matter what i change, I keep getting errors. looks like you need to create a procedure that loops MONTHS_BETWEEN times and use if/else conditions to check if you hit the last month and functions DATEDIFF and LAST_DAY to calculate number of days. p. Search for "Calendars for Finance and Analytics". The date Functions are sub-divided into 7 types of functions. The formula assumes that Saturday and Sunday are not business days. Here is an example Here is an example1. The minus sign (-) can also be used to subtract dates. snowpark. functions. The return value is always of type TIMESTAMP_TZ. The function supports units of years, quarters, months, weeks, days, hours, minutes, seconds, milliseconds, microseconds, and nanoseconds. It is following snowflake's documentation. Pramit Marattha. Supported date and. Alternative for DATE_PART. If { Ignore | Respect } NULL is not specified then default will be Respect Nulls. Make sure that the data type of each column is consistent across the rows from different sources. I use the following where condition as 0 to select the value on today's date. The syntax for using the DATEDIFF function in Snowflake and Amazon Redshift, and Databricks looks like the following: datediff (< date part >, < start date / time >, < end date / time >) A note on Databricks: Databricks additionally supports a separate DATEDIFF function that takes only two arguments: a start date and an end date. 0. If you have extra questions about this answer, please click " Comment ". When operating on a large quantity of data, gaps can appear in a sequence. Das Minuszeichen ( -) kann auch zum Subtrahieren von Datumsangaben verwendet werden. Snowflakeは、整数を秒として解釈することが意図されている場合にのみ、整数を含む文字列で TO. In order to get the integer part of Impala's MONTHS_BETWEEN using Snowflake functions we apply the following logic : IFF(DAY(DATE1) >= DAY(DATE2), DATEDIFF('month', DATE2, DATE1), DATEDIFF('month', DATE2, DATE1) - 1) In order to get the fractional part of Impala's MONTHS_BETWEEN using Snowflake functions we. functions. highest, second-highest, etc. I have used the code contained below to create date and time scaffolds for several clients for various reasons, such as populating records between the “CreateDate” and “CloseDate” of a data point. 0. In Snowflake, it is possible to run stored procedures within a transaction, which means that the changes made by the stored procedure are committed or rolled back as a single unit of work. Covering popular subjects like HTML, CSS, JavaScript, Python, SQL, Java, and many, many more. Didn't know that. Such virtual tables are useful for queries whose SELECT. The function. Improve this question. Step 5: Move the Existing Data Set After your database objects are created in Snowflake, the next step is to move the historical data to Snowflake. 5 * FLOOR ((DATEDIFF (day, date_trunc ('quarter', @s), @e)). For example, you can use interval data type functions to add years, months, days, hours, etc to the timestamp variables. Datediff didn't work: DATEDIFF(hour,2,TO_DATE(substr(p. I understood the sql insert column concept, but got mixed up with $1 of parquet format (parquet data is imported to staging as 1 column data). For full months, you can use day 1. 複数の行が評価される場合（例: 入力が複数の行を含むテーブルの列名である場合）、値が秒. With that, I expect that someone can provide you with a solution for you in Snowflake. 9 and 2. I'm trying to calculate an age value for our users based on their birthday, which one would expect to be a simple enough operation. Also if the deadline_date is NULL, set the number of days as 0. date_to, DATEDIFF(DD, evnt. The collation specifications of all input arguments must be compatible. Start Date & End Date should be Min & Max dates of Sales Fact Table. convert(varchar,cast((End_Datetime-Start_Datetime) as time),108) how to convert this to snowflakesnowflake. I am looking to understand what the average amount of days between transactions is for each of the customers in my database using Snowflake. The datepart value cannot be specified in a variable, nor as a quoted string like 'month'. Any fields using concatenation likely need to be modified. datediff¶. DATETIME is an alias for TIMESTAMP_NTZ. e. 0 to 23. See the supported date and time parts, the calendar week. Declare firstName varchar; Declare lastName varchar; select firstName =FirstNameColumn,lastName =LastNameColumn from User; snowflake-cloud-data-platform; Share. For example, if you want to subtract 7 days from a date, the syntax would be: SELECT DATEADD ( DAY, -7, CURRENT_TIMESTAMP ()) Remember that the interval parameter must be in. Snowflake does not allow to run session variable statement and dashboard query statement together. function. initial_proposal_completed)/ 60 / 24-sum (case when IsSalesWorkday = 0 then 1 else 0 end) diff. 0 to 59.